180m^2-5=0

Solution for 180m^2-5=0 equation:

180m^2-5=0

a = 180; b = 0; c = -5;
Δ = b2-4ac
Δ = 02-4·180·(-5)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*180}=\frac{-60}{360}
=-1/6
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*180}=\frac{60}{360}
=1/6
$